(3x+4)(2x^2-7x+3)=0

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Solution for (3x+4)(2x^2-7x+3)=0 equation:


Simplifying
(3x + 4)(2x2 + -7x + 3) = 0

Reorder the terms:
(4 + 3x)(2x2 + -7x + 3) = 0

Reorder the terms:
(4 + 3x)(3 + -7x + 2x2) = 0

Multiply (4 + 3x) * (3 + -7x + 2x2)
(4(3 + -7x + 2x2) + 3x * (3 + -7x + 2x2)) = 0
((3 * 4 + -7x * 4 + 2x2 * 4) + 3x * (3 + -7x + 2x2)) = 0
((12 + -28x + 8x2) + 3x * (3 + -7x + 2x2)) = 0
(12 + -28x + 8x2 + (3 * 3x + -7x * 3x + 2x2 * 3x)) = 0
(12 + -28x + 8x2 + (9x + -21x2 + 6x3)) = 0

Reorder the terms:
(12 + -28x + 9x + 8x2 + -21x2 + 6x3) = 0

Combine like terms: -28x + 9x = -19x
(12 + -19x + 8x2 + -21x2 + 6x3) = 0

Combine like terms: 8x2 + -21x2 = -13x2
(12 + -19x + -13x2 + 6x3) = 0

Solving
12 + -19x + -13x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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